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x^2+8x+10=93.5
We move all terms to the left:
x^2+8x+10-(93.5)=0
We add all the numbers together, and all the variables
x^2+8x-83.5=0
a = 1; b = 8; c = -83.5;
Δ = b2-4ac
Δ = 82-4·1·(-83.5)
Δ = 398
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{398}}{2*1}=\frac{-8-\sqrt{398}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{398}}{2*1}=\frac{-8+\sqrt{398}}{2} $
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